Answer
I
Work Step by Step
Because $\sin\theta\gt0$ in quadrants I and II and $\tan\theta\gt0$ in quadrants I and III, both conditions are met only in quadrant I.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 520: 112
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