Answer
$\sqrt 3$
Work Step by Step
$1+\cot^{2}\theta=\csc^{2}\theta=-2^{2}=4$
$\cot^{2}\theta=4-1=3$
$\cot\theta=\pm\sqrt {3}$
$\cot\theta$ is positive in the third quadrant.
$\implies \cot\theta=\sqrt 3$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 520: 136
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