Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 107: 140

Answer

a. $C=\frac{x+0.35(200)}{x+200}=\frac{x+70}{x+200}$ b. $300$ liters

Work Step by Step

a. Using the formula given in the previous problem, we have $C=\frac{x+0.35(200)}{x+200}=\frac{x+70}{x+200}$ b. Let $C=74(\%)$; we have $\frac{x+70}{x+200}=0.74$ or $x+70=0.74x+148$ and $0.26x=78$, or $x=300$ liters
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