Answer
Solution set:$ \; \{-3,1\}$
Work Step by Step
$7-7x=(3x+2)(x-1)$
$7-7x=3x^{2}-3x+2x-2$
$7-7x=3x^{2}-x-2$
$0=3x^{2}+6x-9\qquad $... $/\div 3$
$0=x^{2}+2x-3$
Find two factors of $-3$ that add to $+2$; they are $+3$ and $-1$.
$0=(x+3)(x-1)$
$ x=-3, \; x=1.$
Solution set:$ \; \{-3,1\}$
