Answer
See graph and explanations.
Work Step by Step
Step 1. Given $\frac{x^2}{49}+\frac{y^2}{36}=1$, we can identify $a^2=49, b^2=36$; thus $c=\sqrt {a^2-b^2}=\sqrt {13}$. The ellipse is centered at $(0,0)$ with a horizontal major axis.
Step 2. We can graph the equation as shown in the figure, and the foci can be located at $(\pm\sqrt {13},0)$
