Answer
$\frac{x^2}{36}+\frac{y^2}{32}=1$
Work Step by Step
Step 1. Based on the given conditions, we have $c=2, a=6$; thus $b^2=a^2-c^2=32$.
The ellipse is centered at $(0,0)$ with a horizontal major axis.
Step 2. We can write the equation as $\frac{x^2}{36}+\frac{y^2}{32}=1$
