Answer
$\frac{x^2}{13}+\frac{y^2}{9}=1$
Work Step by Step
Step 1. Based on the given conditions, we have $c=2, b=3$; thus $a^2=b^2+c^2=13$.
The ellipse is centered at $(0,0)$ with a horizontal major axis.
Step 2. We can write the equation as $\frac{x^2}{13}+\frac{y^2}{9}=1$
