Answer
See graph and explanations.
Work Step by Step
Step 1. Rewrite the equation as $\frac{x^2}{5}+\frac{y^2}{6}=1$; we can identify $a^2=6, b^2=5$. Thus $c=\sqrt {a^2-b^2}=1$. The ellipse is centered at $(0,0)$ with a vertical major axis.
Step 2. We can graph the equation as shown in the figure, and the foci can be located at $(0,\pm1)$
