Answer
See graph and explanations.
Work Step by Step
Step 1. Rewrite the given equation as $\frac{(x+4)^2}{1}+\frac{(y+3)^2}{36}=1$; we have $a^2=36, b^2=1$ and $c=\sqrt {a^2-b^2}=\sqrt {35}$. The ellipse is centered at $(-4,-3)$ with a vertical major axis.
Step 2. We can graph the equation as shown in the figure with foci at $(-4,-3\pm\sqrt {35})$.
