Answer
See graph and explanations.
Work Step by Step
Step 1. Given $\frac{x^2}{9}+\frac{y^2}{36}=1$, we can identify $a^2=36, b^2=9$; thus $c=\sqrt {a^2-b^2}=3\sqrt 3$. The ellipse is centered at $(0,0)$ with a vertical major axis.
Step 2. We can graph the equation as shown in the figure, and the foci can be located at $(0, \pm3\sqrt 3)$
