Answer
See graph and explanations.
Work Step by Step
Step 1. Rewrite the equation as $x^2+4y^2=1$, we can identify $a^2=1, b^2=\frac{1}{4}$; thus $c=\sqrt {a^2-b^2}=\frac{\sqrt 3}{2}$. The ellipse is centered at $(0,0)$ with a horizontal major axis.
Step 2. We can graph the equation as shown in the figure, and the foci can be located at $(\pm\frac{\sqrt 3}{2},0)$
