Answer
The matrix $ D-A $ is, $ D-A=\left[ \begin{array}{*{35}{l}}
-4 & 4 & -1 \\
-2 & -5 & 5 \\
\end{array} \right]$.
Work Step by Step
Here we need to find $ D-A $. Therefore consider, $\begin{align}
& D-A=\left[ \begin{array}{*{35}{l}}
-2 & 3 & 1 \\
3 & -2 & 4 \\
\end{array} \right]-\left[ \begin{array}{*{35}{l}}
2 & -1 & 2 \\
5 & 3 & -1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
-2-2 & 3+1 & 1-2 \\
3-5 & -2-3 & 4+1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
-4 & 4 & -1 \\
-2 & -5 & 5 \\
\end{array} \right]
\end{align}$
Thus, $ D-A=\left[ \begin{array}{*{35}{l}}
-4 & 4 & -1 \\
-2 & -5 & 5 \\
\end{array} \right]$
