Answer
$(\dfrac{-5}{2}, \dfrac{1}{4})$, $(-4,1)$
Work Step by Step
After using the substitution method, we get
$y=(x+3)^2$
$x+2(x+3)^2=-2$
Re-arrange as: $x+2x^2+12x+18=-2$
This gives: $2x^+13x+20=0 \implies (2x+5)(x+4)$
when $x=\dfrac{-5}{2}$then we have $y=(\dfrac{-5}{2}+3)^2$
This gives: $y=\dfrac{1}{4}$
when $x=-4$ then we have $y=(-4+3)^2$
This gives: $y=1$
Hence, our answers are: $(\dfrac{-5}{2}, \dfrac{1}{4})$, $(-4,1)$
