Chapter 7 - Section 7.4 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 850: 2

$(0,1)$ or $(1,2)$

Here, we have $y=x^2+1$ Now, $x-(x^2+1)=-1$ This gives: $x^2-x=0$ This yields : $x(x-1)=0$ when $x=0$ then we have $y=0+1=1$ and when $x=1$ then we have $y=(1)^2+1=2$ Hence, our answers are: $(0,1)$ or $(1,2)$