Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.1 - Verifying Trigonometric Identities - Exercise Set - Page 660: 70

Answer

$\frac{1}{cotx}$

Work Step by Step

$\frac{1}{sinxcosx}$ - cotx = $\frac{1}{sinxcosx}$ - $\frac{cosx}{sinx}$= $\frac{1-cos^{2}x}{sinxcosx}$ = $\frac{sin^{2}x}{sinxcosx}$=$\frac{sinx}{cosx}$= $\frac{1}{cotx}$
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