Answer
Not defined
Work Step by Step
Suppose $\theta =\sin^{-1}(\pi)$
This gives: $\sin \theta=\sin[\sin^{-1}(\pi)]$
The inverse property states that $\sin^{-1}(\sin a)=a $ satisfies for every $ a $ in the range $[-1,1]$ .
But the value $ a=\pi $ does not lie in the range of $[-1,1]$.
Therefore, we have $ \sin[\sin^{-1}(\pi)]=$ Not defined
