Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 626: 24

Answer

$1.11$

Work Step by Step

Suppose $\theta = \cos^{-1} (\dfrac{4}{9})$ This gives: $\cos \theta=\dfrac{4}{9}$ Now, substitute the equation into a calculator. Therefore, we have $ \cos^{-1} (\dfrac{4}{9})=1.11$
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