Answer
$0.9$
Work Step by Step
Suppose $\theta =\sin^{-1}(0.9)$
This gives: $\sin \theta=\sin [\sin^{-1}(0.9)]$
The inverse property states that $\sin(\sin^{-1} a)=a $ satisfies for every $ a $ in the range $[-1,1]$ .
Therefore, we have $ \sin [\sin^{-1}(0.9)]=0.9$
