Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 626: 16

Answer

$-\dfrac{\pi}{4}$

Work Step by Step

Suppose $\theta = \tan^{-1} (-1)$ This gives: $\tan \theta=1$ Now, $\theta = \tan^{-1} (-1)=-\dfrac{\pi}{4}$ Therefore, $\tan^{-1} (-1)=-\dfrac{\pi}{4}$
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