Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.4 - Trigonometric Functions of Any Angle - Exercise Set - Page 576: 111

Answer

This statement does not make sense.

Work Step by Step

The trigonometric expressions $\sin \theta <0$ and $\csc \theta >0$ can not happen at the same time. Since, $\csc \theta =\frac{1}{\sin \theta }$ We see that $\csc$ and $\sin$ must have the same sign. Thus, the statement does not make sense.
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