Answer
$0$
Work Step by Step
Here, $ x=0$; $ y=1$ and $ r=\sqrt {(0)^2+(1)^2}=1$
The trigonometric ratios are as follows:
$\cot \theta =\dfrac{x}{y}$
Then, we have $\cot (\pi/2) =\dfrac{0}{1}=0$
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