Answer
Undefined
Work Step by Step
Here, $ y= -1$; $ x=0$ and $ r=\sqrt {(1)^2+(0)^2}=1$
The trigonometric ratios are as follows:
$\tan \theta =\dfrac{y}{x}$
Then, we have $\tan (3\pi/2) =\dfrac{-1}{0}=$ Undefined
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