Answer
Undefined or, $\infty $
Work Step by Step
Here, $ x= -1$; $ y=0$ and $ r=\sqrt {(1)^2+(0)^2}=1$
The trigonometric ratios are as follows:
$\csc \theta =\dfrac{r}{y}$
Then, we have $\csc (\pi) =\dfrac{1}{0}=\infty $ or, Undefined
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.4 - Trigonometric Functions of Any Angle - Exercise Set - Page 575: 12
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