Answer
$ a_{1}=16;a_2=-8;a_3=4;a_4=-2;a_5=1$
Work Step by Step
The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$
Here, $ a_n=16(-\dfrac{1}{2})^{n-1}$
Plug $ n=1,2,3,4,5$
$ a_{1}=16(-\dfrac{1}{2})^{1-1}=16;a_2=16(-\dfrac{1}{2})^{2-1}=-8;a_3=16(-\dfrac{1}{2})^{3-1}=4;a_4=16(-\dfrac{1}{2})^{4-1}=-2;a_5=16(-\dfrac{1}{2})^{5-1}=1$
So, the first $5$ terms of the sequence are
$ a_{1}=16;a_2=-8;a_3=4;a_4=-2;a_5=1$