Answer
$ a_1=\dfrac{3}{2};a_2 =1, a_3=\dfrac{1}{2}; a_4=0; a_5= \dfrac{-1}{2}: a_6=-1$
Work Step by Step
We need to use the formula $ a_n =a_1+(n-1) d $ ....(1)
Here, $ a_1=\dfrac{3}{2}$ and $ d=-\dfrac{1}{2}$
Plug $ n=1,2,3,4,5,6$
$ a_1=\dfrac{3}{2} +(1-1) \times (-\dfrac{1}{2}) =\dfrac{3}{2}; a_2=\dfrac{3}{2} +(2-1) \times (\dfrac{-1}{2}) =1$
In order to calculate the first $6$ terms of the sequence, we will have to plug $ n=1,2,3,4,5,6$ into the given equation (1).
So, the first $6$ terms are: $ a_1=\dfrac{3}{2};a_2 =1, a_3=\dfrac{1}{2}; a_4=0; a_5= \dfrac{-1}{2}: a_6=-1$
