Answer
$ a_{1}=3;a_2=6;a_3=12;a_4=24;a_5=48$
Work Step by Step
The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$
Here, $ a_n=3(2)^{n-1}$
Plug $ n=1,2,3,4,5$
$ a_{1}=3(2)^{1-1}=3;a_2=3(2)^{2-1}=6;a_3=3(2)^{3-1}=12;a_4=3(2)^{4-1}=24;a_5=3(2)^{5-1}=48$
So, the first $5$ terms of the sequence are
$ a_{1}=3;a_2=6;a_3=12;a_4=24;a_5=48$
