Chapter 10 - Review Exercises - Page 1124: 29

$418,500$

We need to use the formula $ a_n =a_1+(n-1) d $ Here, $ a_1=31,500$ and $ d=2300$ $ a_{n}=31,500 +(n-1) \times (2300) =29,200+2300n $ or, $ a_{10}=29,200+2300 \times 10=52,200$ Now, $ S_{10}=\dfrac{10(31,500+52,200)}{2}=418,500$