Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1124: 23

Answer

$225$

Work Step by Step

We need to use the formula $ a_n =a_1+(n-1) d $ Here, $ a_1=-6$ and $ d=3$ $ a_{15}=-6 +(15-1) \times (3) =36$ or, $ a_{15}=36$ Now, $ S_{15}=\dfrac{15(-6+36)}{2}=225$
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