Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 176: 48

See the full explanation below.

We have to plot the graphs of functions with the help of the points individually for $f\left( x \right)$ and $g\left( x \right)$. So, the coordinates of $f\left( x \right)$ for $x=-2$ to $x=2$ are as follows: $\begin{align} & x=-2 \\ & f\left( x \right)={{x}^{3}} \\ & ={{\left( -2 \right)}^{3}} \\ & =-8 \end{align}$ $\begin{align} & x=-1 \\ & f\left( x \right)={{x}^{3}} \\ & ={{\left( -1 \right)}^{3}} \\ & =-1 \end{align}$ $\begin{align} & x=0 \\ & f\left( x \right)={{x}^{3}} \\ & ={{\left( 0 \right)}^{3}} \\ & =0 \end{align}$ $\begin{align} & x=1 \\ & f\left( x \right)={{x}^{3}} \\ & ={{\left( 1 \right)}^{3}} \\ & =1 \end{align}$ $\begin{align} & x=2 \\ & f\left( x \right)={{x}^{3}} \\ & ={{\left( 2 \right)}^{3}} \\ & =8 \end{align}$ The coordinates of $g\left( x \right)={{x}^{3}}-1$ for $x=-2$ to $x=2$ are as follows: $\begin{align} & x=-2 \\ & g\left( x \right)={{x}^{3}}-1 \\ & ={{\left( -2 \right)}^{3}}-1 \\ & =-9 \end{align}$ $\begin{align} & x=-1 \\ & g\left( x \right)={{x}^{3}}-1 \\ & ={{\left( -1 \right)}^{3}}-1 \\ & =-2 \end{align}$ $\begin{align} & x=0 \\ & g\left( x \right)={{x}^{3}}-1 \\ & ={{\left( 0 \right)}^{3}}-1 \\ & =-1 \end{align}$ $\begin{align} & x=1 \\ & g\left( x \right)={{x}^{3}}-1 \\ & ={{\left( 1 \right)}^{3}}-1 \\ & =0 \end{align}$ $\begin{align} & x=2 \\ & g\left( x \right)={{x}^{3}}-1 \\ & ={{\left( 2 \right)}^{3}}-1 \\ & =7 \end{align}$