Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 306: 96

Answer

$y=\frac{\sqrt C\sqrt[6] {x^2+1}}{\sqrt[4] x}$

Work Step by Step

Step 1. Isolate $ln(y)$ to get $ln(y)=-\frac{1}{4}ln(x)+\frac{1}{6}(x^2+1)+\frac{1}{2}lnC$ Step 2. Combine the right side to get $ln(y)=ln\frac{\sqrt C\sqrt[6] {x^2+1}}{\sqrt[4] x}$ Step 3. Thus $y=\frac{\sqrt C\sqrt[6] {x^2+1}}{\sqrt[4] x}$
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