Answer
One real solution of multiplicity 2.
Work Step by Step
Use the discriminant, we have $b^2-4ac=28^2-4(4)(49)=0$. Thus the equation has a real solution of multiplicity 2.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 306: 116
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