Answer
$y=\frac{\sqrt[3] C\ \sqrt[6] {2x+1}}{\sqrt[9] {x+4}}$
Work Step by Step
Step 1. Combine the right side to get $3ln(y)=ln\frac{C\sqrt {(2x+1)}}{\sqrt[3] {x+4}}$
Step 2. We have $ln(y)=\frac{1}{3}ln\frac{C\sqrt {(2x+1)}}{\sqrt[3] {x+4}}$
Step 3. Thus $y=\frac{\sqrt[3] C\ \sqrt[6] {2x+1}}{\sqrt[9] {x+4}}$
