Answer
$\approx-3.907$
Work Step by Step
Using The Change-of-Base Formula $\log_a{b}=\dfrac{\log_c{b}}{\log_c{a}}$ and then evaluating using a calculator gives
$\log_{\frac{1}{2}}15=\dfrac{\log15}{\log\frac{1}{2}}\approx-3.907$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 306: 74
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