Answer
$-26$
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
\]
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence here $D=4((-1)\cdot4-0\cdot(-3))-(-1)(6\cdot4-0\cdot1)+(2)(6\cdot(-3)-(-1)\cdot1)=4(-4)-(-1)(24)+(2)(-17)=-16+24-34=-26.$