Answer
$10$
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
\]
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence here $D=3((-1)\cdot(-2)-5\cdot2)-4(1\cdot(-2)-5\cdot1)+2(1\cdot2-(-1)\cdot1)=3(-8)-4(-7)+2(3)=-24+28+6=10.$