Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 363: 104

Answer

\[x=\frac{4}{3}\]

Work Step by Step

The equation is\[-2\left\{ 7-\left[ 4-2\left( 1-x \right)+3 \right] \right\}=10-\left[ 4x-2\left( x-3 \right) \right]\]. Use the order of operations, \[\begin{align} & -2\left\{ 7-\left[ 4-2\left( 1-x \right)+3 \right] \right\}=10-\left[ 4x-2\left( x-3 \right) \right] \\ & -2\left\{ 7-\left[ 4-2+2x+3 \right] \right\}=10-\left[ 4x-2x+6 \right] \\ & -2\left\{ 7-\left[ 5+2x \right] \right\}=10-\left[ 2x+6 \right] \\ & -2\left\{ 7-5-2x \right\}=10-2x-6 \end{align}\] Further simplification, \[\begin{align} & -2\left\{ 2-2x \right\}=4-2x \\ & -4+4x=4-2x \end{align}\] Add\[2x\]to both sides of the equal sign, \[\begin{align} & -4+4x+2x=4-2x+2x \\ & -4+6x=4 \end{align}\] Add \[4\]to both sides of the equal sign, \[\begin{align} & -4+6x+4=4+4 \\ & 6x=8 \\ & x=\frac{8}{6} \\ & x=\frac{4}{3} \end{align}\] Therefore, the value of \[x=\frac{4}{3}\]
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