Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 363: 102

Answer

\[x=0\]

Work Step by Step

The equation is\[0.5\left( x+2 \right)=0.1+3\left( 0.1x+0.3 \right)\]. Use the order of operations, \[\begin{align} & 0.5\left( x+2 \right)=0.1+3\left( 0.1x+0.3 \right) \\ & 0.5x+1=0.1+0.3x+0.9 \\ & 0.5x+1=0.3x+1 \end{align}\] Subtract \[1\] from both sides of the equal sign, \[\begin{align} & 0.5x+1-1=0.3x+1-1 \\ & 0.5x=0.3x \end{align}\] Subtract \[0.3x\] from both sides of the equal sign, \[\begin{align} & 0.5x-0.3x=0 \\ & 0.2x=0 \\ & x=\frac{0}{0.2} \\ & x=0 \end{align}\] Therefore, \[x=0\]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.