Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 363: 101

Answer

\[x=10\]

Work Step by Step

The equation is \[0.7x+0.4\left( 20 \right)=0.5\left( x+20 \right)\]. Use the order of operations, \[\begin{align} & 0.7x+0.4\left( 20 \right)=0.5\left( x+20 \right) \\ & 0.7x+8=0.5x+10 \end{align}\] Subtract \[0.5x\] from both sides of the equal sign, \[\begin{align} & 0.7x+8-0.5x=0.5x+10-0.5x \\ & 0.2x+8=10 \end{align}\] Subtract \[8\] from both sides of the equal sign, \[\begin{align} & 0.2x+8-8=10-8 \\ & 0.2x=2 \\ & x=\frac{2}{0.2} \\ & x=10 \end{align}\] Therefore, \[x=10\]
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