University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Section 10.3 - Polar Coordinates - Exercises - Page 577: 18

Answer

Graph:

Work Step by Step

Plotting points $(r,\theta)$ , $r$ is the directed distance of the point from the pole. $\theta$ defines the angle of the ray on which the point lies, - remains $\theta$ when $r$ is positive - becomes $\theta\pm\pi$ when $r$ is negative The region is such that: The angle $11\pi/4$ terminates in the 2nd quadrant, as $ 11\pi/4=3\pi/4+2\pi$ defines a line through the pole (the origin) with slope $\tan( 11\pi/4) =-1.$ $11\pi/4$ terminates in the 2nd quadrant, but the directed distance r is partly negative, from -1 to 0, so some points in the opposite (4th) quadrant are involved. These are points on the line that are at a distance 1 or less from the pole. For the rest of the values of r, the points represented lie on the ray through the 2nd quadrant.
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