University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Section 10.3 - Polar Coordinates - Exercises - Page 577: 16

Answer

Graph:

Work Step by Step

Plotting points $(r,\theta)$ , $r$ is the directed distance of the point from the pole. $\theta$ defines the angle of the ray on which the point lies, - remains $\theta$ when $r$ is positive - becomes $\theta\pm\pi$ when $r$ is negative The points $(r,\theta)$ of the region are such that: The angle $2\pi/3$ defines a line through the pole (the origin) with slope $\tan( 2\pi/3) =-\sqrt{3}.$ $2\pi/3$ terminates in the 2nd quadrant, but the directed distance r is negative, so only points in the opposite (4th) quadrant are involved. Also, $r \leq -2$ means that these points (on the ray are at least two units away from the pole). The graph is the ray with initial point on the circle of radius 2, quadrant IV.
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