Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.7 - Hyperbolic Functions - Exercises 7.7 - Page 431: 66

Answer

$\ln(2-\sqrt{3})$

Work Step by Step

Substitute into the relevant formula: $\displaystyle \mathrm{c}\mathrm{s}\mathrm{c}\mathrm{h}^{-1}(-\frac{1}{\sqrt{3}})=\ln[\frac{1}{-\frac{1}{\sqrt{3}}}+\frac{\sqrt{1+(-\frac{1}{\sqrt{3}}})^{2}}{|-\frac{1}{\sqrt{3}}|}]$ $=\displaystyle \ln[-\sqrt{3}+\frac{\sqrt{4/3}}{\frac{1}{\sqrt{3}}}]$ $=\ln[-\sqrt{3}+\sqrt{3}\sqrt{4/3}]$ $=\ln[-\sqrt{3}+\sqrt{4}]$ $=\ln(2-\sqrt{3})$
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