Answer
$\frac{e^{2y}}{2}$ = $e^{x}+C$
Work Step by Step
$\frac{dy}{dx}$ = $\frac{e^{2x-y}}{e^{x+y}}$
$\frac{dy}{dx}$ = ${e^{2x-y-x-y}}$
$\frac{dy}{dx}$ = ${e^{x-2y}}$
$e^{2y}dy$ = $e^{x}dx$
$\int(e^{2y})dy$ = $\int(e^{x})dx$
$\frac{e^{2y}}{2}$ = $e^{x}+C$