Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 175: 50

Answer

$1\%$

Work Step by Step

Step 1. Volume $V=\frac{\pi D^3}{6}$ where $D$ is the diameter. We have $dV=\frac{\pi D^2dD}{2}$ and $\frac{dV}{V}=\frac{\frac{\pi D^2dD}{2}}{\frac{\pi D^3}{6}}=\frac{3dD}{D}$ Step 2. We need $\frac{dV}{V}\leq3\%$ that is $\frac{3dD}{D}\leq3\%$ or $\frac{dD}{D}\leq1\%$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.