Answer
a.0.4641
b.0.4
c the approximation of error =0.0641
Work Step by Step
as x.=1,dx=0.1
x.+dx=1+0.1
=1.1
as given formula in part a
=1.1^4 -1^4
=1.4641-1
=0.4641
b. df/dx=4x^3
df=4(1)^3 * dx
df=4*0.1
df=0.4
c. the approximation error
=I0.4641-0.4I
=0.0641