Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 175: 36

Answer

$dV=3x_0^2dx$

Work Step by Step

Step 1. Given $V=x^3$, we have $dV=3x^2dx$ Step 2. The change in the volume when $x_0$ changes to $x_0+dx$ is then given by $dV=3x_0^2dx$
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