Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 26

Answer

$x=\frac{3}{2}$

Work Step by Step

$\frac{2x-3}{x}-\frac{2x-3}{x+1}=0$ $(2x-3)(\frac{1}{x}-\frac{1}{x+1})=0$ $\frac{(2x-3)(x+1-x)}{x(x+1)}=0$ $\frac{(2x-3)}{x(x+1)}=0$ $x=\frac{3}{2}$
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