Answer
$x=\frac{3}{2}$
Work Step by Step
$\frac{2x-3}{x}-\frac{2x-3}{x+1}=0$
$(2x-3)(\frac{1}{x}-\frac{1}{x+1})=0$
$\frac{(2x-3)(x+1-x)}{x(x+1)}=0$
$\frac{(2x-3)}{x(x+1)}=0$
$x=\frac{3}{2}$
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