Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 24

Answer

$x=0$

Work Step by Step

$\frac{2x-3}{x-1}-\frac{2x+3}{x+1}=0$ $\frac{(2x-3)(x+1)-(2x+3)(x-1)}{(x-1)(x+1)}=0$ $\frac{(2x^{2}-x-3)-(2x^{2}+x-3)}{(x-1)(x+1)}=0$ $\frac{-2x}{(x-1)(x+1)}=0$ $x=0$
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