Answer
$x=0, \pm 1$
Work Step by Step
$(x^{2}+1)\sqrt[3] (x+1)^{4}-\sqrt[3] (x+1)^{7}=0$
$(\sqrt[3] (x+1)^{4})(x^{2}+1-x-1)=0$
$(\sqrt[3] (x+1)^{4})(x^{2}-x)=0$
$(\sqrt[3] (x+1)^{4})x(x-1)=0$
$x=0, -1, 1$
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