Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 19

Answer

$x=1, x=-1$

Work Step by Step

$\frac{x-1}{x}=0$ $\frac{x^{2}-1}{x}=0$ $\frac{(x+1)(x-1)}{x}=0$ $x=1, x=-1$
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