Answer
$x=-1, -\frac{3}{2}, -2$
Work Step by Step
$(x+1)^{2}(2x+3)-(x+1)(2x+3)^{2}=0$
$(x+1)(2x+3)(x+1-2x-3)=0$
$(x+1)(2x+3)(-x-2)=0$
$x=-1, -\frac{3}{2}, -2$
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